Chef and Chefina : CFCFNA | Codechef Solution

Problem

Given the time control of a chess match as a+b, determine which format of chess out of the given 4 it belongs to.

1. Chef if a + b \lt 3a+b<3
2. Cfenia if 3 \leq a + b \leq 103≤a+b≤10
3. Chefina if 11 \leq a + b \leq 6011≤a+b≤60
4. Cf if 60 \lt a + b60<a+b.

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Input Format

1. First line will contain T, number of testcases. Then the testcases follow.
2. Each testcase contains a single line of input, two integers a, b.

Output Format

For each testcase, output in a single line.

Constraints

Sample

Input

4

1 0

4 1

100 0

20 5

Output

1

2

4

3

Explanation

TestCase 1: Since a+b=1<3.

TestCase 2: Since 3≤(a+b=5)≤10.

Solution

        
cpp
        

            
        
     
#include <iostream>
using namespace std;
class Chess{
    int a,b,c;
    public:
    void game();
    
};
void Chess::game(){
    cin>>a>>b;
    c=a+b;
    if(c<3)
    cout<<1<<endl;
    else if(c>=3&&c<=10)
    cout<<2<<endl;
    else if(c>=11&&c<=60)
    cout<<3<<endl;
    else
    cout<<4<<endl;
    
}
int main() {
	// your code goes here
	int t;
	cin>>t;
	Chess c;
	while(t--){
	    c.game();
	}
	return 0;
}

        
java
        

            
        
     
/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc=new Scanner(System.in);
        int t=sc.nextInt();
        while(t-->0){
            int a=sc.nextInt();
            int b=sc.nextInt();
            if(a+b<3)System.out.println("1");
            else if (3<=a+b&&a+b<=10)System.out.println("2");
            else if (11<=a+b&&a+b<=60)System.out.println("3");
            else System.out.println("4");
        }
	}
}

        
python
        

            
        
     
# cook your dish here
for _ in range(int(input())):
    a,b=map(int,input().split())
    if (a+b)<3:
        print("1")
    elif (a+b)<=10 and (a+b)>=3:
        print("2")
    elif (a+b)<=60 and (a+b)>=11:
        print("3")
    else:
        print("4")

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