ATM : HS08TEST | Codechef Solution

Problem

Pooja would like to withdraw X $US from an ATM. The cash machine will only accept the transaction if X is a multiple of 5, and Pooja's account balance has enough cash to perform the withdrawal transaction (including bank charges). For each successful withdrawal the bank charges 0.50 $US.

Calculate Pooja's account balance after an attempted transaction.

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Input Format

Positive integer 0 < X <= 2000 - the amount of cash which Pooja wishes to withdraw.

Nonnegative number 0<= Y <= 2000 with two digits of precision - Pooja's initial account balance.

Output Format

Output the account balance after the attempted transaction, given as a number with two digits of precision. If there is not enough money in the account to complete the transaction, output the current bank balance.

Constraints

Sample

Input

30 120.00

Output

89.50

Explanation

Solution

#include <iostream>
using namespace std;

// Solution from : Code Radius [ https://radiuscode.blogspot.com/ ]

int main() {
 int w;
    float ac_bl;
    cin>>w;
    cin>>ac_bl;
    if(w%5==0 && w<=ac_bl-0.5){
        cout<<((ac_bl-w)-(0.5));
    }
    else{
        cout<<ac_bl;
    }
 return 0;
}

import java.util.*;
import java.io.*;

class Solution{
    public static void main(String[] args) throws Exception{
        InputStreamReader i = new InputStreamReader(System.in);
        BufferedReader bf = new BufferedReader(i);
        String[] in = bf.readLine().split(" ");
        float n = Float.parseFloat(in[0]);
        float f = Float.parseFloat(in[1]);
        
        if(n%5==0 && f>=n+0.5f)
        System.out.println(f-n-0.5f);
        
        else{
            System.out.println(f);
        }
        
    }
}

n,atm=map(float,input().split())
n=int(n)
if (n+0.5<=atm and n%5==0):
    print(float(atm-n-0.5))
else:
    print(float(atm))

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